Move all zeroes to end of array (Using single traversal)

Hello Everyone,

Questions: Given an array of n numbers. The problem is to move all the 0’s to the end of the array while maintaining the order of the other elements. Only single traversal of the array is required.
Examples:

Input : arr[] = {1, 2, 0, 0, 0, 3, 6} Output : 1 2 3 6 0 0 0 Input: arr[] = {0, 1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0, 9} Output: 1 9 8 4 2 7 6 9 0 0 0 0 0

Algorithm:

moveZerosToEnd(arr, n) Initialize count = 0 for i = 0 to n-1 if (arr[i] != 0) then swap(arr[count++], arr[i])

• CPP

`// C++ implementation to move all zeroes at`

`// the end of array`

`#include <iostream>`

`using` `namespace` `std;`

`// function to move all zeroes at`

`// the end of array`

`void` `moveZerosToEnd(` `int` `arr[], ` `int` `n)`

`{`

` ` `// Count of non-zero elements`

` ` `int` `count = 0;`

` ` `// Traverse the array. If arr[i] is non-zero, then`

` ` `// swap the element at index 'count' with the`

` ` `// element at index 'i'`

` ` `for` `(` `int` `i = 0; i < n; i++)`

` ` `if` `(arr[i] != 0)`

` ` `swap(arr[count++], arr[i]);`

`}`

`// function to print the array elements`

`void` `printArray(` `int` `arr[], ` `int` `n)`

`{`

` ` `for` `(` `int` `i = 0; i < n; i++)`

` ` `cout << arr[i] << ` `" "` `;`

`}`

`// Driver program to test above`

`int` `main()`

`{`

` ` `int` `arr[] = { 0, 1, 9, 8, 4, 0, 0, 2,`

` ` `7, 0, 6, 0, 9 };`

` ` `int` `n = ` `sizeof` `(arr) / ` `sizeof` `(arr[0]);`

` ` `cout << ` `"Original array: "` `;`

` ` `printArray(arr, n);`

` ` `moveZerosToEnd(arr, n);`

` ` `cout << ` `"\nModified array: "` `;`

` ` `printArray(arr, n);`

` ` `return` `0;`

`}`

Output:

Original array: 0 1 9 8 4 0 0 2 7 0 6 0 9
Modified array: 1 9 8 4 2 7 6 9 0 0 0 0 0

Time Complexity: O(n).
Auxiliary Space: O(1).